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How can i get the result of the Cascaded Biquad Filters? Could you like to gave the equation for me? thanks a lot!

Processors & DSP shihong sun Sep 11, 2019 00:00 0 replies Original on forum ↗
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shihong sun Question
Sep 11, 2019 00:00

In the upper diagram, there are two cascated filters. Than how can i get the result 'y(n)' in time domain. In other words , how to express y(n) with the given 2-group parameters. The difficult for me is how to deal with the relationship between the two cascated filters. And I also know the difference equation should be as follows:

y(n)=b0.x(n)+b1.x(n-1)+b2.x(n-2)-a1.y(n-1)-a2.y(n-2);

But how to derive it from the parameters of the 2 cascated filters . Thanks!

截图20190911152739.png
截图20190911152739.png