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How to use basic Second order filter to implement the Linkwitz-Riley Filter

SigmaDSP & SigmaStudio Davids Oct 24, 2019 00:00 2 replies Original on forum ↗
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Davids Question
Oct 24, 2019 00:00

Hi,

I am trying to implement the Linkwitz-Riley Filter,

as I refer this website (https://www.rane.com/note160.html#ref)

from this section:

"Taken to its most general extremes, cascading any order Butterworth filter produces 2x that order Linkwitz-Riley. Hence, cascading two 1st-order circuits produces a 2nd-order Linkwitz-Riley (LR-2); cascading two 2nd-order Butterworth filters creates a LR-4 design; cascading two 3rd-order Butterworth filters gives a LR-6, and so on. (Starting with LR-2, every other solution requires inverting one output. That is, LR-2 and LR-6 need inverting, while LR-4 and LR-8 do not.)"

and I try the basic High or Low pass filter(second-order) to simulate the butterworth filter.

I use second-order filter and Q-factor = 0.707 (Sigmastudio will change to 0.71, but is the same result).

and the next I try to use the simulated butterworth filter to make one Linkwitz-Riley 12 (as I know it is a 2nd-order Linkwitz-Riley)

Using Crossover I take the result will like this:

If I want to take the Flat result, the Crossover block need to invert the polarity.

if not invert the polarity will like this:

As the above idea, I use the simulated butterworth filter and trying to make the crossover,

but however I invert the signal phase, I can not get the correct answer, here is how I do:

but no invert the polarity will same as the crossover tool:

Anything that I missunderstand?

Please help mine question

BR,

Alvis

sigma studio

Second-order filter

filter

Linkwitz-Riley filter

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KJBob Reply
Oct 25, 2019 00:00

Hello Alvis,

The Rane article describes the LR-24 as two 2nd order Butterworth (Q = 0.707) lowpass and highpass filters. This works as described:

The LR-12 was often made back in the day with resistors and caps, thus has a lower Q than even a Butterworth filter. If you use Q = 0.5, the crossover works as intended:

Best regards,

Bob

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Davids Reply
Nov 6, 2019 00:00

Hello Bob,

Thank you for replying me!

This Help me a lot :)

and below is I try by myself to make a LR-12

I use phase invert to achieve that, so is it same as your sub tool?

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